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formulas-termodinamica

Thermodynamics and Heat Transfer Formulas

Laws of Thermodynamics

Zeroth Law of Thermodynamics

If two systems are in thermal equilibrium with a third system, then they are in thermal equilibrium with each other.

First Law of Thermodynamics

where,

  • : Change in internal energy
  • : Heat added to the system
  • : Work done by the system

Second Law of Thermodynamics

In a reversible cycle, the heat absorbed is greater than the work done:

Third Law of Thermodynamics

As the temperature of a system approaches absolute zero, the entropy of a system reaches a constant minimum.

State Properties

Internal Energy

where,

  • : Temperature
  • : Volume
  • : Number of moles

Enthalpy

where,

  • : Enthalpy
  • : Pressure
  • : Volume

Entropy

  • where,
  • : Change in entropy
  • : Reversible heat
  • : Temperature

Inefficiency of Processes

where

  • is the change in entropy. For reversible processes,

Entropy at Absolute Zero

Change in Entropy

where

  • is the heat absorbed in a reversible process

Entropy in Isothermal Processes

Change in Entropy in an Ideal Gas

Thermodynamic Processes

Isothermal Process

Work Done in an Isothermal Process

Isochoric Process

where,

Isobaric Process

where,

  • : Heat capacity at constant pressure

Adiabatic Process

where,

For an ideal gas:

Thermal Equilibrium

Condition for Thermal Equilibrium

whereis the heat entering the system andis the heat leaving.

State Equations

Ideal Gas State Equation

where:

  • : Universal gas constant

Internal Energy of an Ideal Gas

where:

  • = number of moles
  • = heat capacity at constant volume (J/(mol·K))
  • = temperature (K)

Van der Waals Equation

where:

  • : Corrects the pressure
  • : Corrects the volume

Work and Heat

Work

Work done by a system:

W = \int P , dV

W = nRT \ln \left( \frac{V_f}{V_i} \right)

You can't use 'macro parameter character #' in math mode#### Heat Specific heat at constant volume:

Q = nC_v \Delta T

Q = nC_p \Delta T

You can't use 'macro parameter character #' in math mode## Heat Capacities #### Heat Capacity at Constant Pressure

Q = nC_p\Delta T

You can't use 'macro parameter character #' in math modewhere: - $C_p$ = heat capacity at constant pressure (J/(mol·K)) - $\Delta T$ = change in temperature (K) #### Relationship between $C_p$ and $C_v$

C_p - C_v = R

You can't use 'macro parameter character #' in math mode## Carnot Cycle #### Temperatures in the Carnot Cycle The efficiency of the Carnot cycle depends on the temperatures of the hot and cold sources: - Temperature of the hot source $T_H$ - Temperature of the cold source $T_C$ These temperatures must be expressed in **kelvin (K)**. #### Efficiency of the Carnot Cycle The efficiency of the Carnot cycle is defined as the fraction of heat absorbed that is converted into work. This efficiency depends only on the temperatures of the hot and cold sources:

\eta = 1 - \frac{T_C}{T_H}

You can't use 'macro parameter character #' in math modeWhere: - $ \eta $ = efficiency of the Carnot cycle (dimensionless, usually expressed as a percentage) - $ T_H $ = temperature of the hot source (in Kelvin) - $ T_C $ = temperature of the cold source (in Kelvin) #### Heat Transferred in the Carnot Cycle In a Carnot cycle, heat is absorbed and released during the isothermal processes. **Heat absorbed from the hot source $ Q_H $**

Q_H = n R T_H \ln\left(\frac{V_B}{V_A}\right)

Q_C = n R T_C \ln\left(\frac{V_D}{V_C}\right)

You can't use 'macro parameter character #' in math modeWhere: - $ T_C $ = temperature of the cold source (in Kelvin) - $ V_D $ and $ V_C $ = initial and final volumes during the isothermal compression. #### Work Done in the Carnot Cycle The net work done by a Carnot cycle is the difference between the heat absorbed and the heat released:

W = Q_H - Q_C

W = n R \left(T_H \ln\left(\frac{V_B}{V_A}\right) - T_C \ln\left(\frac{V_D}{V_C}\right)\right)

You can't use 'macro parameter character #' in math mode#### Relationship between Volume and Temperature in Adiabatic Processes During adiabatic processes, there is no heat transfer. The relationship between volume and temperature in an adiabatic process for an ideal gas is given by:

V_B T_H^{\gamma-1} = V_A T_C^{\gamma-1}

You can't use 'macro parameter character #' in math modeWhere $ \gamma $ is the adiabatic coefficient or specific heat ratio ($ \gamma = \frac{C_P}{C_V} $). #### Relationship between Work and Efficiency The work done can also be related to the efficiency of the Carnot cycle:

W = \eta Q_H

You can't use 'macro parameter character #' in math modeWhere: - $ W $ = net work done by the cycle - $ Q_H $ = heat absorbed from the hot source - $ \eta $ = efficiency of the Carnot cycle #### Entropy in the Carnot Cycle The total change in entropy in a Carnot cycle is zero since it is a reversible cycle: **Change in entropy in the hot source**

\Delta S_H = \frac{Q_H}{T_H}

\Delta S_C = \frac{Q_C}{T_C}

\frac{Q_H}{T_H} = \frac{Q_C}{T_C}

You can't use 'macro parameter character #' in math mode#### Inverse Carnot Cycle (Refrigeration) For an inverse Carnot cycle, used in refrigeration, the **coefficient of performance (COP)** is defined as: **COP for refrigerator**

COP_{\text{ref}} = \frac{Q_C}{W} = \frac{T_C}{T_H - T_C}

COP_{\text{cal}} = \frac{Q_H}{W} = \frac{T_H}{T_H - T_C}

You can't use 'macro parameter character #' in math modeWhere: - $ Q_C $ = heat extracted from the cold source - $ Q_H $ = heat delivered to the hot source - $ W $ = work done in the cycle ## Rankine Cycle #### Components of the Rankine Cycle The Rankine cycle consists of four main components: - **Heater** (water heater) - **Turbine** (steam expansion) - **Condenser** (steam condensation) - **Pump** (liquid pressurization) #### Efficiency of the Rankine Cycle The efficiency of the Rankine cycle can be calculated as the ratio of the net work done to the heat absorbed in the heater:

\eta = \frac{W_{\text{net}}}{Q_H} = \frac{W_{\text{turbine}} - W_{\text{pump}}}{Q_H}

You can't use 'macro parameter character #' in math modeWhere: - $ W_{\text{net}} $ = net work done by the cycle - $ Q_H $ = heat absorbed in the heater #### Work Done by the Turbine and Pump The work done by the turbine and the pump is expressed as follows: **Work of the turbine**

W_{\text{turbine}} = h_1 - h_2

W_{\text{pump}} = h_4 - h_3

You can't use 'macro parameter character #' in math modeWhere: - $ h_1 $ = enthalpy of the steam at the turbine inlet - $ h_2 $ = enthalpy of the steam at the turbine outlet - $ h_3 $ = enthalpy of the liquid at the pump outlet - $ h_4 $ = enthalpy of the liquid at the heater inlet ### Heat Transferred in the Rankine Cycle The heat absorbed and released in the Rankine cycle is calculated as follows: #### Heat absorbed in the heater

Q_H = h_1 - h_4

You can't use 'macro parameter character #' in math mode#### Heat released in the condenser

Q_C = h_2 - h_3

You can't use 'macro parameter character #' in math modeWhere: - $ Q_H $ = heat absorbed in the heater - $ Q_C $ = heat released in the condenser ### Energy and Entropy The Rankine cycle can be analyzed in terms of energy and entropy. The change in entropy in each component is: #### Change in entropy in the turbine

\Delta S_{\text{turbine}} = s_2 - s_1

You can't use 'macro parameter character #' in math mode#### Change in entropy in the pump

\Delta S_{\text{pump}} = s_4 - s_3

You can't use 'macro parameter character #' in math modeWhere: - $ s_1, s_2, s_3, s_4 $ are the entropies at each state of the cycle. The cycle must be reversible for the total entropy of the system not to increase. #### Relationship between Efficiency and Work The relationship between the efficiency of the Rankine cycle and the work done can be expressed as:

\eta = 1 - \frac{Q_C}{Q_H}

You can't use 'macro parameter character #' in math mode#### Ideal vs. Real Rankine Cycle The efficiency of the ideal Rankine cycle is based on the fact that all processes are reversible and adiabatic. For real Rankine cycles, efficiency is affected by losses and cannot be calculated as directly. However, an approximation can be given as:

\eta_{\text{real}} \approx \eta_{\text{ideal}} - \text{losses}

You can't use 'macro parameter character #' in math mode#### Work in the Rankine Cycle The net work done by the Rankine cycle is calculated as:

W_{\text{net}} = W_{\text{turbine}} - W_{\text{pump}} = (h_1 - h_2) - (h_4 - h_3)

You can't use 'macro parameter character #' in math mode#### Coefficient of Performance (COP) The Rankine cycle can be used in heating applications, and its **coefficient of performance (COP)** is defined as:

COP = \frac{Q_H}{W_{\text{net}}}

You can't use 'macro parameter character #' in math mode### 10. Pressure Considerations The Rankine cycle can be analyzed at different pressures. The work and heat also depend on the pressure and temperature conditions: **Pressure in the condenser $ P_C $** **Pressure in the boiler $ P_H $** The efficiency and net work of the cycle can be significantly affected by the operating pressure. ## Otto and Diesel Cycles ### Introduction to the Cycles - Otto Cycle Used in gasoline engines, characterized by a higher compression ratio and a constant **volume** combustion process. - Diesel Cycle Used in diesel engines, characterized by a higher compression ratio and a constant **pressure** combustion process. ### Efficiency of the Cycle #### Efficiency of the Otto Cycle The efficiency of the Otto cycle can be calculated as:

\eta_{Otto} = 1 - \frac{1}{r^{\gamma-1}}

You can't use 'macro parameter character #' in math modeWhere: - $ r $ = compression ratio - $ \gamma $ = specific heat ratio ($ \gamma = \frac{C_P}{C_V} $) #### Efficiency of the Diesel Cycle The efficiency of the Diesel cycle is calculated as:

\eta_{Diesel} = 1 - \frac{1}{r^{\gamma-1}} \cdot \frac{\alpha^\gamma - 1}{\alpha (\gamma - 1)}

You can't use 'macro parameter character #' in math modeWhere: - $ \alpha $ = expansion ratio (the compression ratio of the Otto cycle is different from the expansion ratio of the Diesel cycle) - $ r $ = compression ratio - $ \gamma $ = specific heat ratio ### Work Done in the Cycles #### Work in the Otto Cycle The work done by an Otto cycle is expressed as:

W_{Otto} = Q_{in} - Q_{out} = \frac{C_V (T_2 - T_1)}{1 - r^{1-\gamma}}

You can't use 'macro parameter character #' in math mode#### Work in the Diesel Cycle The work done by a Diesel cycle is:

W_{Diesel} = Q_{in} - Q_{out} = C_V (T_3 - T_2) - C_V (T_4 - T_3)

You can't use 'macro parameter character #' in math mode### Heat Transferred in the Cycles #### Heat Absorbed in the Otto Cycle The heat absorbed in the Otto cycle is expressed as:

Q_{in} = m \cdot C_V (T_2 - T_1)

You can't use 'macro parameter character #' in math mode#### Heat Absorbed in the Diesel Cycle The heat absorbed in the Diesel cycle is:

Q_{in} = m \cdot C_P (T_3 - T_2)

You can't use 'macro parameter character #' in math mode### Temperature Relationships in the Cycles #### Otto Cycle The temperatures in the Otto cycle can be related to the compression ratio:

\frac{T_2}{T_1} = r^{\gamma - 1}

\frac{T_3}{T_2} = \frac{T_1}{T_4}

You can't use 'macro parameter character #' in math mode#### Diesel Cycle The temperatures in the Diesel cycle are related as follows:

\frac{T_2}{T_1} = r^{\gamma - 1}

\frac{T_4}{T_3} = \frac{1}{\alpha^{\gamma - 1}}

You can't use 'macro parameter character #' in math mode### State Equations #### State Equation for Otto Cycle For an ideal gas in the Otto cycle:

PV = nRT

You can't use 'macro parameter character #' in math mode#### State Equation for Diesel Cycle Similarly, for the Diesel cycle:

PV = nRT

You can't use 'macro parameter character #' in math mode### Relationship between Pressure and Volume #### Otto Cycle The relationship between pressure and volume during the Otto cycle is described by:

PV^\gamma = \text{constant}

You can't use 'macro parameter character #' in math mode#### Diesel Cycle The relationship between pressure and volume during the Diesel cycle is:

PV = nRT

You can't use 'macro parameter character #' in math mode### Coefficient of Performance (COP) Although the Otto and Diesel cycles are not used in refrigeration, the **coefficient of performance** can be defined in a broader context, such as the performance of the cycles:

COP = \frac{Q_{in}}{W_{neto}}

You can't use 'macro parameter character #' in math modeWhere: - $ W_{neto} $ is the net work done by the cycle. ## Carrier Cycles #### Introduction to Carrier Cycles Carrier cycles are a type of thermodynamic cycle used in refrigeration and air conditioning systems. They are based on the transfer of heat through a refrigerant, which circulates in a closed cycle. #### Components of the Carrier Cycle Carrier cycles typically include the following components: - Compressor Increases the pressure of the refrigerant - Condenser The refrigerant releases heat and condenses from vapor to liquid - Expansion valve Reduces the pressure of the liquid refrigerant - Evaporator The refrigerant absorbs heat and evaporates ### Efficiency of the Carrier Cycle The efficiency of a Carrier cycle can be calculated using the **coefficient of performance (COP)**: #### Coefficient of Performance (COP) The COP is defined as the ratio of the heat extracted from the refrigerated space to the work done by the compressor:

COP = \frac{Q_{evaporator}}{W_{compressor}}